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  • How do we determine the required dependencies for ffmpeg

    15 mars 2021, par user3656901

    I've installed ffmpeg on ubuntu. I am going to copy the compiled ffmpeg and required dependencies to a directory and copy that directory to another machine. This way we can run ffmpeg on another machine without installation. How do we determine the required dependencies to copy ? Saw instruction on this page : https://trac.ffmpeg.org/wiki/CompilationGuide/Ubuntu, but it didn't explain the required dependencies for ffmpeg.

    


    When I used ldd ffmpeg, I got something like :

    


        linux-vdso.so.1 (0x00007fffe20fd000)
    libavdevice.so.58 => /lib/x86_64-linux-gnu/libavdevice.so.58 (0x00007fc116e90000)
    libavfilter.so.7 => /lib/x86_64-linux-gnu/libavfilter.so.7 (0x00007fc116b10000)
    libavformat.so.58 => /lib/x86_64-linux-gnu/libavformat.so.58 (0x00007fc116890000)
    libavcodec.so.58 => /lib/x86_64-linux-gnu/libavcodec.so.58 (0x00007fc1152d0000)
    libavresample.so.4 => /lib/x86_64-linux-gnu/libavresample.so.4 (0x00007fc1152a0000)
    libpostproc.so.55 => /lib/x86_64-linux-gnu/libpostproc.so.55 (0x00007fc115270000)


    


    Are those the required dependencies ? It didn't list the files under bin, include or share folders.

    


  • sh : ffmpeg : command not found when run command through php

    21 septembre 2018, par Vivacity InfoTech

    I have installed successfully installed FFMpeg on root of my Centos 6 machine (https://trac.ffmpeg.org/wiki/CompilationGuide/Centos).

    My workplace of apache/php is /var/www/html

    Now I’m running below command successfully on /var/www/html directory to capture frame from the video file. It’s capturing a frame.

    [root@localhost html]# ffmpeg -i video.mpg -an -ss 30  -t 00:00:01 -r 1 -y -vcodec mjpeg -f mjpeg -s 160x100 frame8  2>&1

    I want to run this command through php and using shell_exec() or exec() php functions. My php code for running the command is :

    $cmd = "/root/bin/ffmpeg -i /project/app/webroot/videos/video.mpg -ss 00:00:14.435 -f image2 -vframes 1 /project/app/webroot/videothumbnails/example-thumb.jpg";
    
$locale = 'en_IN.UTF-8';
    
setlocale(LC_ALL, $locale);
    
putenv('LC_ALL='.$locale);
    
echo shell_exec($cmd);

    When I’m trying to run command through above php code, I’m getting below error :

    sh: ffmpeg: command not found

    Please help me to solve out this problem.

  • sh : ffmpeg : command not found when run command through php

    9 avril 2015, par Ashok

    I have installed successfully installed FFMpeg on root of my Centos 6 machine (https://trac.ffmpeg.org/wiki/CompilationGuide/Centos).

    My workplace of apache/php is /var/www/html

    Now I’m running below command successfully on /var/www/html directory to capture frame from the video file. It’s capturing a frame.

    [root@localhost html]# ffmpeg -i video.mpg -an -ss 30  -t 00:00:01 -r 1 -y -vcodec mjpeg -f mjpeg -s 160x100 frame8  2>&1

    I want to run this command through php and using shell_exec() or exec() php functions. My php code for running the command is :

    $cmd = "/root/bin/ffmpeg -i /project/app/webroot/videos/video.mpg -ss 00:00:14.435 -f image2 -vframes 1 /project/app/webroot/videothumbnails/example-thumb.jpg";
    
$locale = 'en_IN.UTF-8';
    
setlocale(LC_ALL, $locale);
    
putenv('LC_ALL='.$locale);
    
echo shell_exec($cmd);

    When I’m trying to run command through above php code, I’m getting below error :

    sh: ffmpeg: command not found

    Please help me to solve out this problem.

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