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2023-04-18 18:25:05 INFO discord.player ffmpeg process ##### successfully terminated with return code of 0
19 avril 2023, par I_am_thingI am making a discord music bot with discord.py and ctx, it uses Spotify


I am using FFmpeg for my music feature. This is my !play code


client_id = ''
client_secret = ''
client_credentials_manager = SpotifyClientCredentials(client_id=client_id, client_secret=client_secret)
sp = spotipy.Spotify(client_credentials_manager=client_credentials_manager)

bot.volume = 0.5 # initial volume of the bot (can be changed)

@bot.command()
async def play(ctx, *, track_query):
 # check if the query is a valid Spotify link
 if 'open.spotify.com/track/' in track_query:
 track_id = track_query.split('/')[-1] # extract the track ID from the link
 else:
 # search for tracks with the given name
 track_results = sp.search(q=track_query, type='track', limit=1)
 if len(track_results['tracks']['items']) == 0:
 await ctx.send(f'Sorry, I could not find any track with the name "{track_query}".')
 return
 track_id = track_results['tracks']['items'][0]['id'] # get the track ID for the first search result
 track_info = sp.track(track_id) # get the track information for the given ID
 track_name = track_info['name']
 track_artist = track_info['artists'][0]['name']
 track_duration = time.strftime('%M:%S', time.gmtime(track_info['duration_ms']//1000))
 track_preview_url = track_info['preview_url'] # get the preview URL for the track
 if track_preview_url is None:
 await ctx.send(f'Sorry, the track "{track_name}" by {track_artist} cannot be played.')
 return
 voice_channel = ctx.author.voice.channel
 if voice_channel is None:
 await ctx.send('Please join a voice channel first.')
 return
 voice_client = await voice_channel.connect()
 audio_source = discord.FFmpegPCMAudio(track_preview_url, options="-b:a 128k -bufsize 512k")
 voice_client.play(audio_source, after=lambda e: print('Player error: %s' % e) if e else None)
 voice_client.source = discord.PCMVolumeTransformer(voice_client.source)
 voice_client.source.volume = bot.volume

 # format the embed message
 embed = discord.Embed(title=track_name, description=track_artist, color=0xff8c00)
 embed.add_field(name='Duration', value=track_duration, inline=True)
 embed.set_thumbnail(url=track_info['album']['images'][0]['url'])
 embed.set_footer(text='This music is from https://www.spotify.com/')
 await ctx.send(embed=embed)

 while voice_client.is_playing():
 await asyncio.sleep(1)
 await voice_client.disconnect()



I joined the unofficial ffmpeg discord server no one could find a fix I searched for ages and I couldn't fix it


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Anomalie #2023 : Interface privée : le lien "informations personnelles" ne fonctionne plus sous 2....
6 avril 2011, par cedric -Je ne reproduis pas. J’ai bien un lien fonctionnel. Si tu ne le constates que sur un seul site, c’est peut être la faute d’un plugin ?
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Anomalie #2023 : Interface privée : le lien "informations personnelles" ne fonctionne plus sous 2....
6 avril 2011, par gvincent -Effectivement je ne reproduits pas le bug sur un site en [16966]. Je vais voir sans aucun plugin (j’aurais dû commencer par là)