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  • OSError : MoviePy error : the file guitar.mp4 could not be found

    9 septembre 2023, par dunnjm814

    I'm working on a video to audio converter with react and flask/python.
I have received a 500 with this error :

    


    raise IOError(("MoviePy error: the file %s could not be found!\n"
OSError: MoviePy error: the file guitar.mp4 could not be found!
Please check that you entered the correct path.


    


    EDIT : As stated in comments, moviepy VideoFileClip is looking for a path. Per suggestion, I am now attempting to write the incoming video file to a temp directory housed in the backend of the app. The updated stack trace shows the filepath printing, however when presented to VideoFileClip it is still unhappy.

    


    The following snippet is the onSubmit for the video file upload :

    


    const onSubmit = async (e) => {
    e.preventDefault()
    const data = new FormData()
    console.log('hopefully the mp4', videoData)
    data.append('mp3', videoData)
    console.log('hopefully a form object with mp4', data)
    const response = await fetch('/api/convert', {
      method: "POST",
      body: data
    })
    if (response.ok) {
      const converted = await response.json()
      setMp3(converted)
      console.log(mp3)
    } else {
      window.alert("something went wrong :(");
    }
  }


    


    Here is a link to an image depicting the console output of my file upload
from within init.py

    


    app = Flask(__name__)

app.config.from_object(Config)
app.register_blueprint(convert, url_prefix='/api/convert')

CORS(app)



    


    from within converter.py

    


    import os
from flask import Blueprint, jsonify, request
import imageio
from moviepy.editor import *


convert = Blueprint('convert', __name__)

@convert.route('', methods=['POST'])
def convert_mp4():
  if request.files['mp3'].filename:
    os.getcwd()
    filename = request.files['mp3'].filename
    print('hey its a file again', filename)
    safe_filename = secure_filename(filename)
    video_file = os.path.join("/temp/", safe_filename)
    print('hey its the file path', video_file)
    video_clip = VideoFileClip(video_file)
    print('hey its the VideoFileClip', video_clip)
    audio_clip = video_clip.audio
    audio_clip.write_audiofile(os.path.join("/temp/", f"{safe_filename}-converted.mp3"))

    video_clip.close()
    audio_clip.close()

    return jsonify(send_from_directory(os.path.join("/temp/", f"{safe_filename}-converted.mp3")))
  else:
    return {'error': 'something went wrong :('}




    


    In the stack trace below you can see file printing the name of the video, my only other thought on why this may not be working was because it was getting lost in the post request, however the fact it is printing after my if file: check is leaving me pretty confused.

    


    hey its a file again guitar.mp4
hey its the file path /temp/guitar.mp4
127.0.0.1 - - [22/Apr/2021 12:12:15] "POST /api/convert HTTP/1.1" 500 -
Traceback (most recent call last):
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 2464, in __call__
    return self.wsgi_app(environ, start_response)
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 2450, in wsgi_app
    response = self.handle_exception(e)
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask_cors/extension.py", line 161, in wrapped_function
    return cors_after_request(app.make_response(f(*args, **kwargs)))
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 1867, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/_compat.py", line 39, in reraise
    raise value
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 2447, in wsgi_app
    response = self.full_dispatch_request()
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 1952, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask_cors/extension.py", line 161, in wrapped_function
    return cors_after_request(app.make_response(f(*args, **kwargs)))
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 1821, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/_compat.py", line 39, in reraise
    raise value
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 1950, in full_dispatch_request
    rv = self.dispatch_request()
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/flask/app.py", line 1936, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/jasondunn/projects/audioconverter/back/api/converter.py", line 20, in convert_mp4
    video_clip = VideoFileClip(video_file)
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/moviepy/video/io/VideoFileClip.py", line 88, in __init__
    self.reader = FFMPEG_VideoReader(filename, pix_fmt=pix_fmt,
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/moviepy/video/io/ffmpeg_reader.py", line 35, in __init__
    infos = ffmpeg_parse_infos(filename, print_infos, check_duration,
  File "/home/jasondunn/projects/audioconverter/.venv/lib/python3.8/site-packages/moviepy/video/io/ffmpeg_reader.py", line 270, in ffmpeg_parse_infos
    raise IOError(("MoviePy error: the file %s could not be found!\n"
OSError: MoviePy error: the file /temp/guitar.mp4 could not be found!
Please check that you entered the correct path.


    


    thanks in advance for taking a look/future advice. First official post on Stack Overflow :)

    


  • Virtual Private Server Hosting Price [on hold]

    4 novembre 2015, par Cybernet Web Design

    Can you tell me a VPS that has an unlimited bandwidt a low price but very powerful for streaming website ?

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  • Using ffplay to open a video at a specific window location [on hold]

    18 août 2014, par Willette Lynch

    I need to use ffplay to open a video file, but i need to pass it x,y coordinates so i can have it play the video where I want it to.

    As default ffplay simply opens the video at the top left corner.

    I’ve tried searching for options in ffplay but i couldnt find it.
    Also tried using window managers like fluxbox, again couldnt find the command)

    Please note that I need to run it as a shell command.

    Any Help would be appreciated.

    Thanks in Advance

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