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Rennes Emotion Map 2010-11
19 octobre 2011, par
Mis à jour : Juillet 2013
Langue : français
Type : Texte
Autres articles (35)
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Les tâches Cron régulières de la ferme
1er décembre 2010, parLa gestion de la ferme passe par l’exécution à intervalle régulier de plusieurs tâches répétitives dites Cron.
Le super Cron (gestion_mutu_super_cron)
Cette tâche, planifiée chaque minute, a pour simple effet d’appeler le Cron de l’ensemble des instances de la mutualisation régulièrement. Couplée avec un Cron système sur le site central de la mutualisation, cela permet de simplement générer des visites régulières sur les différents sites et éviter que les tâches des sites peu visités soient trop (...) -
L’agrémenter visuellement
10 avril 2011MediaSPIP est basé sur un système de thèmes et de squelettes. Les squelettes définissent le placement des informations dans la page, définissant un usage spécifique de la plateforme, et les thèmes l’habillage graphique général.
Chacun peut proposer un nouveau thème graphique ou un squelette et le mettre à disposition de la communauté. -
Publier sur MédiaSpip
13 juin 2013Puis-je poster des contenus à partir d’une tablette Ipad ?
Oui, si votre Médiaspip installé est à la version 0.2 ou supérieure. Contacter au besoin l’administrateur de votre MédiaSpip pour le savoir
Sur d’autres sites (7658)
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How can I convert a mp4 file to webm using java only ?
31 octobre 2023, par mir-shakirI am trying to convert a file from mp4 to webm. I am trying to use the JAVE wrapper of FFmpeg. I am getting the error.
Here is my code :


private String ConvertVideo(URL url) {
 File target =null;
 MultimediaObject multimediaObject = new MultimediaObject(url);
 try {
 target = File.createTempFile("target", ".webm");

 } catch (IOException e1) {
 e1.printStackTrace();
 }
 AudioAttributes audio = new AudioAttributes();
 audio.setCodec(AudioAttributes.DIRECT_STREAM_COPY);
 audio.setBitRate(new Integer(128000));
 audio.setSamplingRate(new Integer(44100));
 audio.setChannels(new Integer(2));
 VideoAttributes video = new VideoAttributes();
 video.setBitRate(new Integer(160000));
 video.setFrameRate(new Integer(15));
 video.setCodec("libvpx-vp9");
 video.setCodec(VideoAttributes.DIRECT_STREAM_COPY);
 EncodingAttributes attrs = new EncodingAttributes();
 attrs.setFormat("webm");
 attrs.setAudioAttributes(audio);
 attrs.setVideoAttributes(video);
 
 try {
 Encoder encoder = new Encoder(); 
 encoder.encode(multimediaObject, target, attrs);
 } catch (Exception e) { 
 e.printStackTrace();
 }
 
 return "success";
}



I am getting the below error :


2022-Jun-13 11:12:55 AM [qtp1914526580-175] ERROR ws.schild.jave.Encoder - Process exit code: 1 to target2636257785060285182.webm
ws.schild.jave.EncoderException: Exit code of ffmpeg encoding run is 1



What am I doing wrong here. Is there any other way around it ? I want to do it only using java.


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VLC RTSP HTML5 transcoding
30 mai 2022, par PierogiI'm trying to get audio streaming on an HTML page from an RTSP server.


The RTSP server is the rtsp-simple-server running a command line below.

./rtsp-simple-server rtsp-simple-server.yml
.

The configure file is the default.

The stream player is FFmpeg running a command line below.

ffmpeg -re -stream_loop -1 -i myaudio.mp3 -c copy -f rtsp -rtsp_transport tcp rtsp://localhost:8554/mystream


The console log at the time the rtsp-simple-server and the ffmpeg are started is below.


2022/05/29 19:06:38 INF rtsp-simple-server v0.18.4
2022/05/29 19:06:38 INF [RTSP] listener opened on :8554 (TCP), :8000 (UDP/RTP), :8001 (UDP/RTCP)
2022/05/29 19:06:38 INF [RTMP] listener opened on :1935
2022/05/29 19:06:38 INF [HLS] listener opened on :8888
2022/05/29 19:09:16 INF [RTSP] [conn [::1]:62737] opened
2022/05/29 19:09:16 INF [RTSP] [session 271690815] created by [::1]:62737
2022/05/29 19:09:16 INF [RTSP] [session 271690815] is publishing to path 'mystream', 1 track with TCP



And the time the rtsp path(rtsp ://localhost:8554/mystream) is opened by VLC, the contents can be played properly. The additional console log at the time is below.


2022/05/29 19:13:19 INF [RTSP] [conn 127.0.0.1:62780] opened
2022/05/29 19:13:19 INF [RTSP] [session 734209460] created by 127.0.0.1:62780
2022/05/29 19:13:19 INF [RTSP] [session 734209460] is reading from path 'mystream', 1 track with UDP
2022/05/29 19:13:29 INF [RTSP] [session 734209460] destroyed (teared down by 127.0.0.1:62780)
2022/05/29 19:13:29 INF [RTSP] [conn 127.0.0.1:62780] closed (EOF)
2022/05/29 19:13:29 INF [RTSP] [conn 127.0.0.1:62781] opened
2022/05/29 19:13:29 INF [RTSP] [session 445756113] created by 127.0.0.1:62781
2022/05/29 19:13:29 INF [RTSP] [session 445756113] is reading from path 'mystream', 1 track with TCP



However, I open the rtsp streaming from the VLC's "Network" tab like below,



and configure the "Stream output" like below,



and I tried to get this streaming from an HTML page like below,




 
 
 
 
 
 <h1>transcode test</h1>
 <audio src="http://localhost:9999/mystream" autoplay="autoplay"></audio>
 




the browser console displays
Failed to load resource: the server responded with a status of 404 (Not found)
. I've already tried other ports(etc. 8080).

So, how can I get the rtsp stream from the RTSP server on an HTML page.
Any idea ?


My environment.


- 

- Browser : Microsoft edge
- OS : MacOS 11.6.5
- rtsp-simple-server : 0.18.4
- FFmpeg : 5.0.1
- VLC : 3.0.17.3












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ffmpeg Batch Replace MP4 Thumbnails
1er juin 2022, par pgloveWindows 10, 2022 build of ffmpeg


I found this command to replace the thumbnails on mp4 files :


ffmpeg -i video.mp4 -i image.png -map 1 -map 0 -c copy -disposition:0 attached_pic out.mp4



here :
How do I add a custom thumbnail to a .mp4 file using ffmpeg ?


I have modified it to use jpg instead of png, and have a folder full of videos and images.


ffmpeg -i ###.mp4 -i ###.jpg -map 1 -map 0 -c copy -disposition:0 attached_pic ###-new.mp4



Every mp4 has an alpha-numeric name with a corresponding jpg of the same name.


I generated a list of commands I would need for each file, so I have 100 commands.


If I copy and paste one line at a time it works, but when I copy and paste all 100 lines into the command line on windows it seems like one or two files process as expected, but the rest fail.


I'm pretty sure I'm just missing a step, and any help would be much appreciated turning it into a batch process.


Thanks


*I just tried with 2 lines, the first processed, the second stopped.


Some feedback would be nice if I've posed the question poorly, not provided enough information, or done something else wrong to deserve a downvote already. I don't use forums very often, I try to only ask when I'm stumped, so perhaps my etiquette is poor. I thought I followed correct procedure...