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• How to pipe a new command after ffmpeg background process completes ? (PHP)

  12 septembre 2013, par Mike Feng

  Ok this is my ffmpeg process :

  exec("/usr/local/bin/ffmpeg -y -i source.avi dest.mp4 >/dev/null 2>/dev/null &

  Now, I wish to execute a php file after the conversion is complete. Logically, this is what I have :

  exec("/usr/local/bin/ffmpeg -y -i source.avi dest.mp4 >/dev/null 2>/dev/null ; php proceed.php &

  This doesn't work though, since then PHP will hold up the process to wait till the ffmpeg conversion is complete. What I want is basically to call proceed.php after the conversion completes, both of which are done in the background.

  If anyone can provide the Windows server solution, that will be awesome too. Thank you in advanced !

• NodeJS - How to pipe same video stream to multiple clients ?

  30 août 2013, par SergioBR

  We have a situation trying to serve a video stream.

  Since HTML5 video tag does not support udp to multicast, we are trying to re-use an already converted ffmpeg stream and send it to more than one response. But that does not work.

  The first response gets the stream alright, but the second one does not.
  It seems that the stream cannot be piped out to another response, neither can it be cloned.

  Has anyone done that before ? Any ideas ?

  Thanks in advance !

  Here's the code :

  var request = require('request');
  
  var http = require('http');
  
  var child_process = require("child_process");
  
  var n = 1;
  
  var stdouts = {};
  
  
  
  http.createServer(function (req, resp) {
  
  
  
  console.log("***** url ["+req.url+"], call "+n);
  
  
  
  if (req.url != "/favicon.ico" && req.url != "/")
  
  {
  
  var params = req.url.substring(1).split("/");
  
  
  
  switch (params[0])
  
  {
  
    case "VIEW":
  
      if (params[1] == "C2FLOOR1" || params[1] == "C2FLOOR2" || params[1] == "C2PORFUN" || params[1] == "C2TESTCAM")
  
        var camera = "rtsp://192.168.16.19:554/Inter/Cameras/Stream?Camera="+params[1];
  
      else
  
        var camera = "http://192.168.16.19:8609/Inter/Cameras/GetStream?Camera="+params[1];
  
  
  
      // Write header
  
      resp.writeHead(200, {'Content-Type': 'video/ogg', 'Connection': 'keep-alive'});
  
  
  
      if (stdouts.hasOwnProperty(params[1]))
  
      {
  
        console.log("Getting stream already created for camera "+params[1]);
  
  
  
        var newStdout = Object.create(stdouts[params[1]]);
  
  
  
        newStdout.pipe(resp);
  
      }
  
      else
  
      {
  
          // Start ffmpeg
  
          var ffmpeg = child_process.spawn("ffmpeg",[
  
          "-i",camera,
  
          "-vcodec","libtheora",
  
          "-qscale:v","7",        // video quality
  
          "-f","ogg",             // File format
  
          "-g","1",               // GOP (Group Of Pictures) size
  
          "-"                     // Output to STDOUT
  
          ]);
  
  
  
          stdouts[params[1]] = ffmpeg.stdout;
  
  
  
          // Pipe the video output to the client response
  
          ffmpeg.stdout.pipe(resp);
  
  
  
      console.log("Initializing camera at "+camera);
  
      }
  
  
  
      // Kill the subprocesses when client disconnects
  
  /*
  
      resp.on("close",function(){
  
        ffmpegs[params[1]].kill();
  
        console.log("FIM!");
  
      });
  
  */
  
      break;
  
  }
  
  }
  
  else
  
  {
  
  resp.writeHeader(200, {"Content-Type": "text/html"});
  
  resp.write("WRONG CALL");
  
  resp.end();
  
  }
  
  n++;
  
  
  
  }).listen(8088);
  
  
  
  console.log('Server running at port 8088');

• is it possible to send ffmpeg images by using pipe ?

  18 août 2018, par Yanshof

  I want to send images as input to ffmpeg and I want ffmpeg to output video to a stream (webRtc format.)

  I found some information that from my understanding showed this is possible. - I believe that ffmpeg could receive image from a pipe, does anyone know how this can be done ?