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• Revision 6315 : La limite est automatiquement fixée à 20 si pas présente dans les ...

  7 février 2012, par kent1 — Log

  La limite est automatiquement fixée à 20 si pas présente dans les arguments $what passe en array partout. Le tri, s’il est un string, est traité en amont et transformé en array On incrémente en 0.2.7 On passe en test

• Why does ffmpeg never finish when converting a video from my web app ?

  30 septembre 2011, par Mike

  I am trying to convert a video when the user submits a form. It seems to convert ok but the file "is being used by another proccess" when I try to do anything with it. It looks like ffmpeg.exe never exits. My code is below is there anything I should be doing different to allow the process to release the file ? If I run this manually it exits fine.

  internal class ConversionUtility : Utility
  
  {
  
      public void Convert(string videoFileName)
  
      {
  
          var video = new VideoFile(videoFileName);
  
  
  
          if (!video.infoGathered)
  
              GetVideoInfo(video);
  
  
  
          var Params = string.Format("-y -i \"{0}\" -coder ac -me_method full -me_range 16 -subq 5 -sc_threshold 40 -vcodec libx264 -cmp +chroma -partitions +parti4x4+partp8x8+partb8x8 -i_qfactor 0.71 -keyint_min 25 -b_strategy 1 -g 250 -r 20 \"{1}\"", video.Path, Path.ChangeExtension(videoFileName,".mp4"));
  
          //var Params = string.Format("-y -i \"{0}\" -acodec libfaac -ar 44100 -ab 96k -coder ac -me_method full -me_range 16 -subq 5 -sc_threshold 40 -vcodec libx264 -s 1280x544 -b 1600k -cmp +chroma -partitions +parti4x4+partp8x8+partb8x8 -i_qfactor 0.71 -keyint_min 25 -b_strategy 1 -g 250 -r 20 c:\\output3.mp4", video.Path, videoFileName);
  
          //var Params = String.Format(" {0} \"{1}\"",this.FFmpegLocation, video.Path);
  
  
  
          var threadStart = new ParameterizedThreadStart(del => RunProcess(Params));
  
          var thread = new Thread(threadStart);
  
          thread.Start();            
  
          //RunProcess(Params);
  
      }
  
  }
  
  
  
  internal class Utility
  
  {
  
      public string FFmpegLocation { get; set; }        
  
      private string WorkingPath { get { return Path.GetDirectoryName(FFmpegLocation); } }
  
  
  
      protected string RunProcess(string Parameters)
  
      {
  
          //create a process info
  
          var oInfo = new ProcessStartInfo(this.FFmpegLocation, Parameters)
  
          {
  
              UseShellExecute = false,
  
              CreateNoWindow = true,
  
              RedirectStandardOutput = true,
  
              RedirectStandardError = true
  
          };
  
  
  
          //Create the output and streamreader to get the output
  
          string output = null; StreamReader srOutput = null;
  
  
  
          //try the process
  
          try
  
          {
  
              //run the process
  
              Process proc = System.Diagnostics.Process.Start(oInfo);
  
  
  
              proc.WaitForExit();
  
              //if (!proc.WaitForExit(10000))
  
              //    proc.Kill();
  
  
  
  
  
              //get the output
  
              srOutput = proc.StandardError;
  
  
  
              //now put it in a string
  
              output = srOutput.ReadToEnd();
  
  
  
              proc.Close();
  
          }
  
          catch (Exception)
  
          {
  
              output = string.Empty;
  
          }
  
          finally
  
          {
  
              //now, if we succeded, close out the streamreader
  
              if (srOutput != null)
  
              {
  
                  srOutput.Close();
  
                  srOutput.Dispose();
  
              }
  
          }
  
          return output;
  
      }

• -vf unrecognized with php exec() function

  29 septembre 2011, par Rajat

  I am using php to create a video with fade effects. But exec() function gives following output :

  array(19)
  [0]=>
  string(67) "FFmpeg version 0.6.1, Copyright (c) 2000-2010 the FFmpeg developers"

  [1]=>
  string(74) " built on Dec 4 2010 15:35:31 with gcc 4.1.2 20080704 (Red Hat 4.1.2-48)"

  [2]=>
  string(649) " configuration : —prefix=/usr —libdir=/usr/lib64 —shlibdir=/usr/lib64 —mandir=/usr/share/man —incdir=/usr/include —disable-avisynth —extra-cflags='-O2 -g -pipe -Wall -Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector —param=ssp-buffer-size=4 -m64 -mtune=generic -fPIC' —enable-avfilter —enable-avfilter-lavf —enable-libdirac —enable-libfaac —enable-libfaad —enable-libfaadbin —enable-libgsm —enable-libmp3lame —enable-libopencore-amrnb —enable-libopencore-amrwb —enable-libx264 —enable-gpl —enable-nonfree —enable-postproc —enable-pthreads —enable-shared —enable-swscale —enable-vdpau —enable-version3 —enable-x11grab"

  [3]=>
  string(35) " libavutil 50.15. 1 / 50.15. 1"

  [4]=>
  string(35) " libavcodec 52.72. 2 / 52.72. 2"

  [5]=>
  string(35) " libavformat 52.64. 2 / 52.64. 2"

  [6]=>
  string(35) " libavdevice 52. 2. 0 / 52. 2. 0"

  [7]=>
  string(35) " libavfilter 1.19. 0 / 1.19. 0"

  [8]=>
  string(35) " libswscale 0.11. 0 / 0.11. 0"

  [9]=>
  string(35) " libpostproc 51. 2. 0 / 51. 2. 0"

  [10]=>
  string(122) "Input #0, mov,mp4,m4a,3gp,3g2,mj2, from '/usr/slideshow/frame1.mp4' :"

  [11]=>
  string(11) " Metadata :"

  [12]=>
  string(26) " major_brand : isom"

  [13]=>
  string(25) " minor_version : 512"

  [14]=>
  string(35) " compatible_brands : isomiso2mp41"

  [15]=>
  string(33) " encoder : Lavf52.64.2"

  [16]=>
  string(58) " Duration : 00:00:05.00, start : 0.000000, bitrate : 31 kb/s"

  [17]=>
  string(107) " Stream #0.0(und) : Video : mpeg4, yuv420p, 320x240 [PAR 1:1 DAR 4:3], 29
  kb/s, 1 fps, 1 tbr, 1 tbn, 1 tbc"

  [18]=>
  string(24) "Unrecognized option 'vf'"
  

  Why it is giving unrecognized option 'vf' while it works fine when run directly on server.My command is : "ffmpeg -i /usr/slideshow/frame1.mp4 -vf 'fade=out:0:5' /usr/slideshow/fade1.mp4"

  I am executing it with exec() function. Why the error is coming and what should i use to apply filter to my input video. I am working on CentOS server.

  Please guide me...