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• How to use (django-celery,RQ) worker to execute a video filetype conversion (ffmpeg) in django on heroku (My code works locally)

  15 janvier 2013, par GetItDone

  One part of my website includes a form that allows users to upload video. I use ffmpeg to convert the video to flv. My media and static files are stored on Amazon S3. I can get everything to work perfectly locally, however I can't seem to figure out how to use a worker to run the video conversion subprocess in production. I have dj-celery and rq installed in my app. The code in my view that I was able to get to work locally is :

  #views.py
  
  def upload_broadcast(request):
  
      if request.method == 'POST':
  
          form = VideoUploadForm(request.POST, request.FILES)
  
          if form.is_valid():
  
              new_video=form.save()
  
              def convert_to_flv(video):
  
                  filename = video.video_upload
  
                  sourcefile = "%s%s" % (settings.MEDIA_ROOT, filename)
  
                  flvfilename = "%s.flv" % video.id
  
                  imagefilename = "%s.png" % video.id
  
                  thumbnailfilename = "%svideos/flv/%s" % (settings.MEDIA_ROOT, imagefilename)
  
                  targetfile = "%svideos/flv/%s" % (settings.MEDIA_ROOT, flvfilename)
  
                  ffmpeg = "ffmpeg -i %s -acodec mp3 -ar 22050 -f flv -s 320x240 %s" % (sourcefile, targetfile)
  
                  grabimage = "ffmpeg -y -i %s -vframes 1 -ss 00:00:02 -an -vcodec png -f rawvideo -s 320x240 %s" % (sourcefile, thumbnailfilename)
  
                  print ("SOURCE: %s" % sourcefile)
  
                  print ("TARGET: %s" % targetfile)
  
                  print ("TARGET IMAGE: %s" % thumbnailfilename)
  
                  print ("FFMPEG TASK CODE: %s" % ffmpeg)
  
                  print ("IMAGE TASK CODE: %s" % grabimage)
  
                  try:
  
                      ffmpegresult = subprocess.call(ffmpeg)
  
                      print "---------------FFMPEG---------------"
  
                      print ffmpegresult
  
                  except:
  
                      print "Not working."
  
                  try:
  
                      videothumbnail = subprocess.call(grabimage)
  
                      print "---------------IMAGE---------------"
  
                      print videothumbnail
  
                  except:
  
                      print "Not working."
  
                  video.flvfilename = flvfilename
  
                  video.videothumbnail = imagefilename
  
                  video.save()
  
  
  
              convert_to_flv(new_video)
  
  
  
              return HttpResponseRedirect('/video_list/')
  
      else:
  
  ...

  This is my first time trying to use a worker (or ever pushing a project to production), so even with the documentation it is still unclear to me what I need to do. I have tried several different things but nothing seems to work. Is there just a simple way to tell celery to run the ffmpegresult = subprocess.call(ffmpeg) ? Thanks in advance for any help or insight.

  EDIT- Added heroku logs

  2013-01-10T20:58:57+00:00 app[web.1]: TARGET: /media/videos/flv/8.flv
  
  2013-01-10T20:58:57+00:00 app[web.1]: IMAGE TASK CODE: ffmpeg -y -i /media/videos/practice.wmv -vframes 1 -ss 00:00:02 - an -vcodec png -f rawvideo -s 320x240 /media/videos/flv/8.png
  
  2013-01-10T20:58:57+00:00 app[web.1]: SOURCE: /media/videos/practice.wmv
  
  2013-01-10T20:58:57+00:00 app[web.1]: FFMPEG TASK CODE: ffmpeg -i /media/videos/practice.wmv -acodec mp3 -ar 22050 -f fl v -s 320x240 /media/videos/flv/8.flv
  
  2013-01-10T20:58:57+00:00 app[web.1]: TARGET IMAGE: /media/videos/flv/8.png
  
  2013-01-10T20:58:57+00:00 app[web.1]: Not working.
  
  2013-01-10T20:58:57+00:00 app[web.1]: Not working.

  NEWER EDIT

  I tried adding a tasks.py and added the task :

  celery = Celery('tasks', broker='redis://guest@localhost//')
  
  
  
  @celery.task
  
  def ffmpeg_task(video):
  
      converted_file = subprocess.call(video)
  
      return converted_file

  then I changed the relevant section of my view to :

  ...
  
  try:
  
      ffmpeg_task.delay(ffmpeg)
  
      print "---------------FFMPEG---------------"
  
      print ffmpegresult
  
  except:
  
      print "Not working."
  
  ...

  My new logs are :

  2013-01-15T13:19:52+00:00 app[web.1]: TARGET IMAGE: /media/videos/flv/12.png
  
  2013-01-15T13:19:52+00:00 app[web.1]: SOURCE: /media/videos/practice.wmv
  
  2013-01-15T13:19:52+00:00 app[web.1]: FFMPEG TASK CODE: ffmpeg -i /media/videos/practice.wmv -acodec mp3 -ar 22050 -f fl v -s 320x240 /media/videos/flv/12.flv
  
  2013-01-15T13:19:52+00:00 app[web.1]: IMAGE TASK CODE: ffmpeg -y -i /media/videos/practice.wmv -vframes 1 -ss 00:00:02 -an -vcodec png -f rawvideo -s 320x240 /media/videos/flv/12.png
  
  2013-01-15T13:19:52+00:00 app[web.1]: TARGET: /media/videos/flv/12.flv
  
  2013-01-15T13:20:17+00:00 app[web.1]: 2013-01-15 13:20:17 [2] [CRITICAL] WORKER TIMEOUT (pid:12)
  
  2013-01-15T13:20:17+00:00 app[web.1]: 2013-01-15 13:20:17 [2] [CRITICAL] WORKER TIMEOUT (pid:12)
  
  2013-01-15T13:20:17+00:00 app[web.1]: 2013-01-15 13:20:17 [19] [INFO] Booting worker with pid: 19

  Am I completely missing something ? I'll keep trying, but will be very appreciative of any direction or assistance.

• is Cloud API's needed for Video Conversion to save huge time ?

  7 juillet 2017, par user2224250

  I have seen a couple of ffmpeg software’s which converts a video x format (1.8 GB) to y format (1.8 GB) in less than 90 seconds

  For example IDealshare VideoGo

  When I work with ffmpeg in the terminal, these sort of conversions takes atleast one hour. Moreover, when I compare to the above software, am facing a very very big number interms of time.

  May be, do you think for these fast conversions, we must take help from third party cloud API’s (software’s) such as amazon elastic transcoder etc etc.

  Any pointers would be really appreciable !!

• Modify video with FFMPEG before uploading to S3

  12 juillet 2017, par user774615

  When a user uploads a video, I want to remove its audio. So in my Laravel code, I have something like this :

  // The video from the HTML form
  
  $video = $request->file('video');
  
  
  
  // Strip the audio
  
  exec('ffmpeg -y -i ' . <path to="to" file="file"> . ' -an -c copy ' . <new file="file" path="path">);
  
  </new></path>

  The problem is, I want to upload the final video (without audio) to Amazon’s S3 without saving any part of the video on my local server.

  Is there a way to use $video as the input for the ffmpeg command and then output the result directly to S3 ? How ?