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    The vocabulary used on this site and around MediaSPIP in general, aims to avoid reference to Web 2.0 and the companies that profit from media-sharing.
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    9 février 2011, par

    Dans beaucoup d’endroits du site, logos et images sont redimensionnées pour correspondre aux emplacements définis par les thèmes. L’ensemble des ces tailles pouvant changer d’un thème à un autre peuvent être définies directement dans le thème et éviter ainsi à l’utilisateur de devoir les configurer manuellement après avoir changé l’apparence de son site.
    Ces tailles d’images sont également disponibles dans la configuration spécifique de MediaSPIP Core. La taille maximale du logo du site en pixels, on permet (...)

Sur d’autres sites (6897)

  • Unable to execute CLI commands through PHP

    13 janvier 2012, par user940154

    OS : ubuntu 11.10
    Webserver : Apache
    Code : PHP
    I am trying to display the output of command "ffmpeg -i " on the webpage using php.
    Required : The webpage should show the information about video (text).
    Whats happening : The webpage shows no text output on running the php code.
    If I was however doing system("ls") the code runs fine and outputs the list of files.
    Here's my code

    <?php
    
 echo "Details of video file:";
    
 system('ffmpeg -i /home/atish/Videos/T2V0040006_Angled_ride_720x576i_FLDCMB.avi');
    
?>

    The same command works fine on my shell, and my system has ffmpeg installed. Here's a snapshot of executing this command directly on shell :

    ThinkPad-T420:~/Videos$ ffmpeg -i /home/xx/Videos/T2V0040006_Angled_ride_720x576i_FLDCMB.avi
    
ffmpeg version git-2012-01-10-7e2ba2d Copyright (c) 2000-2012 the FFmpeg developers
    
built on Jan 10 2012 12:01:19 with gcc 4.6.1
    
configuration: --enable-gpl --enable-libfaac --enable-libmp3lame --enable-libopencore-    amrnb --enable-libopencore-amrwb --enable-libtheora --enable-libvorbis --enable-libx264 --enable-nonfree --enable-postproc --enable-version3 --enable-x11grab
    
  libavutil      51. 34.100 / 51. 34.100
    
  libavcodec     53. 54.100 / 53. 54.100
    
  libavformat    53. 29.100 / 53. 29.100
    
  libavdevice    53.  4.100 / 53.  4.100
    
  libavfilter     2. 58.100 /  2. 58.100
    
  libswscale      2.  1.100 /  2.  1.100
    
  libswresample   0.  6.100 /  0.  6.100
    
  libpostproc    51.  2.100 / 51.  2.100
    
  Input #0, avi, from '/home/atish/Videos/T2V0040006_Angled_ride_720x576i_FLDCMB.avi':
    
  Metadata:
    
  encoder         : Lavf52.23.1
    
  Duration: 00:00:29.00, start: 0.000000, bitrate: 124422 kb/s
    
  Stream #0:0: Video: rawvideo (I420 / 0x30323449), yuv420p, 720x576, 25 tbr, 25 tbn, 25 tbc
    
  At least one output file must be specified

    I have tried appending "DISPLAY=:0" to my command and also done "xhost +" before running php code, but nothing is helping me out.

    Thanks.

  • encoding .avi file from bytearray using ffmpeg in javacv or java

    24 janvier 2012, par Ashwin Yakkundi

    I have converted an .avi file into byte[]. What I need to do is to convert the byte[] back to the original .avi file in java or javacv preferably using ffmpeg.

    The following is the code I used for conversion from .avi into byte[]

    import com.googlecode.javacv.cpp.opencv_core.IplImage;
    
import com.googlecode.javacv.CanvasFrame;
    
import com.googlecode.javacv.FFmpegFrameGrabber;
    

    
import java.io.BufferedInputStream;
    
import java.io.DataInputStream;
    
import java.io.File;
    
import java.io.FileInputStream;
    

    
public class VideoDemoTest1{
    

    
    public static void main(String[] args) throws Exception {
    
        String filename = "/home/ashwin/Desktop/cow.avi";
    

    
        FileInputStream fis = new FileInputStream (filename);
    
        DataInputStream dis = new DataInputStream(fis);
    
        int length = dis.available();
    
        System.out.println("length of InputStream = " + length);
    

    
        byte[] videoByteArray = new byte[(int) length];
    

    
        // Read in the bytes
    
        int offset = 0;
    
        int numRead = 0;
    
        while (offset < videoByteArray.length
    
               && (numRead = dis.read(videoByteArray, offset, videoByteArray.length - offset)) >= 0) {
    
                    offset += numRead;
    
        }
    

    
        System.out.println("length of videoByteArray is " + videoByteArray.length);
    
    }
    
}

  • join audio file in specific time of the video ffmpeg

    25 novembre 2012, par George L.

    i am trying to use the code bellow to merge an audio file at specific time (6th second of my input video) and create a new video autput file but i cant make it work.

    <?php
    

    
exec("/usr/local/bin/ffmpeg -sameq -i /home/xxx/public_html/xxx/video/full.mp4 -itsoffet 6 -i /home/xxx/public_html/xxx/sounds/names/george.mp3 /home/xxx/public_html/xxx/upload/sample.mpg");
    

    

    
?>

    Thank you a lot !

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