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Autres articles (47)
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Diogene : création de masques spécifiques de formulaires d’édition de contenus
26 octobre 2010, parDiogene est un des plugins ? SPIP activé par défaut (extension) lors de l’initialisation de MediaSPIP.
A quoi sert ce plugin
Création de masques de formulaires
Le plugin Diogène permet de créer des masques de formulaires spécifiques par secteur sur les trois objets spécifiques SPIP que sont : les articles ; les rubriques ; les sites
Il permet ainsi de définir en fonction d’un secteur particulier, un masque de formulaire par objet, ajoutant ou enlevant ainsi des champs afin de rendre le formulaire (...) -
Utilisation et configuration du script
19 janvier 2011, parInformations spécifiques à la distribution Debian
Si vous utilisez cette distribution, vous devrez activer les dépôts "debian-multimedia" comme expliqué ici :
Depuis la version 0.3.1 du script, le dépôt peut être automatiquement activé à la suite d’une question.
Récupération du script
Le script d’installation peut être récupéré de deux manières différentes.
Via svn en utilisant la commande pour récupérer le code source à jour :
svn co (...) -
Gestion des droits de création et d’édition des objets
8 février 2011, parPar défaut, beaucoup de fonctionnalités sont limitées aux administrateurs mais restent configurables indépendamment pour modifier leur statut minimal d’utilisation notamment : la rédaction de contenus sur le site modifiables dans la gestion des templates de formulaires ; l’ajout de notes aux articles ; l’ajout de légendes et d’annotations sur les images ;
Sur d’autres sites (3212)
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Best way to have 2 youtube-dl input with ffmpeg and php
8 janvier 2021, par Baraque ObahamasI'm trying to find the best way to combine a youtube-dl link in mp4 format with another youtube-dl link in m4a format to get an mp4 file through ffmpeg & php and to have an output in stdout in order to download the file directly.


With only one file to convert to another format, I managed to do it easily, for example from m4a to mp3 :


$cmd = "youtube-dl -f bestaudio[ext=m4a] --no-part --no-cache-dir --no-warnings --no-progress -o - https://www.youtube.com/watch?v=6Dh-RL__uN4 | ffmpeg -i - -f mp3 -ab 192k -";



But with 2 inputs, it doesn't work :


$cmd = "cat <(youtube-dl -f bestvideo[ext=mp4] --no-part --no-cache-dir --no-warnings --no-progress -o - https://www.youtube.com/watch?v=6Dh-RL__uN4) <(youtube-dl -f bestaudio[ext=m4a] --no-part --no-cache-dir --no-warnings --no-progress -o - https://www.youtube.com/watch?v=6Dh-RL__uN4) > ffmpeg -i - -movflags frag_keyframe+empty_moov+faststart -frag_duration 3600 -c:v copy -c:a copy -f mp4 -";



In this case I get a "said into stderr : "sh : 1 : Syntax error : "(" unexpected")" error.


I guess there must be a better way to do it.
I notice another problem is that on the ffmpeg command there is only one input "-i -". Now there are 2 inputs, there should be I guess "pipe:3" in addition, but so far my tests have not been conclusive.


Full code :


<?php
header('Content-Description: File Transfer');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header("Content-Disposition: attachment; filename=\"ok.mp4\"");
header("Content-Type: application/octet-stream");

$cmd = "cat <(youtube-dl -f bestvideo[ext=mp4] --no-part --no-cache-dir --no-warnings --no-progress -o - https://www.youtube.com/watch?v=6Dh-RL__uN4) <(youtube-dl -f bestaudio[ext=m4a] --no-part --no-cache-dir --no-warnings --no-progress -o - https://www.youtube.com/watch?v=6Dh-RL__uN4) > ffmpeg -i - -movflags frag_keyframe+empty_moov+faststart -frag_duration 3600 -c:v copy -c:a copy -f mp4 -";
$cmd = passthru($cmd, $status);



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streaming to youtube with ffmpeg
6 janvier 2021, par ohroblotI am trying to stream to youtube but the stream health says no data.


ffmpeg -threads:v 2 -threads:a 8 -filter_threads 2 -thread_queue_size 512 \
-i /tmp/thumbs/thumbnail.jpg \
-stream_loop -1 \
-i /tmp/audio/tracks.mp3 \
-filter:v "crop=in_w/2:in_h/2:1920:1280" \
-pix_fmt yuv420p -c:v libx264 -qp:v 19 -profile:v high -rc:v cbr_ld_hq -level:v 4.2 -r:v 60 -g:v 120 -bf:v 3 -refs:v 16 -preset fast -f flv rtmp://a.rtmp.youtube.com/live2/xxx



ffmpeg is shown rendering frames like this :


frame= 1 fps=0.0 q=0.0 size= 236220kB time=04:02:50.73 bitrate= 132.8kbits/s speed=67.3x 
frame= 1 fps=0.0 q=0.0 size= 236872kB time=04:03:30.90 bitrate= 132.8kbits/s speed=67.3x 
frame= 1 fps=0.0 q=0.0 size= 237539kB time=04:04:12.02 bitrate= 132.8kbits/s speed=67.3x 
frame= 1 fps=0.0 q=0.0 size= 238215kB time=04:04:53.69 bitrate= 132.8kbits/s speed=67.4x 
frame= 1 fps=0.0 q=0.0 size= 238869kB time=04:05:34.05 bitrate= 132.8kbits/s speed=67.4x 
frame= 1 fps=0.0 q=0.0 size= 239515kB time=04:06:13.83 bitrate= 132.8kbits/s speed=67.4x 
frame= 1 fps=0.0 q=0.0 size= 240153kB time=04:06:53.14 bitrate= 132.8kbits/s speed=67.5x 



but as far as youtube, no data is being sent over.


What is causing this to fail ?


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ffmpeg cannot open connection tcp ://a.rtmp.youtube.com
13 mars 2024, par Hiji DeuiI want to live stream using ffmpeg, when live on Facebook it runs normally, but when I live on YouTube there is an error, is there anything wrong with the command I entered ? even though the command is the same as live on Facebook, but only the RTMP link has been changed




ffmpeg -re -i out.mp4 -c:v copy -c:a aac -ar 44100 -ab 128k -ac 2 -strict -2 -flags +global_header -bsf:a aac_adtstoasc -bufsize 3000k -f flv "rtmp://a.rtmp.youtube.com/live2/my-key-streaming"







and the output is




ffmpeg version N-55112-g7eb9cf593e-static https://johnvansickle.com/ffmpeg/ Copyright (c) 2000-2020 the FFmpeg developers
 built with gcc 8 (Debian 8.3.0-6)
 configuration: --enable-gpl --enable-version3 --enable-static --disable-debug --disable-ffplay --disable-indev=sndio --disable-outdev=sndio --cc=gcc --enable-fontconfig --enable-frei0r --enable-gnutls --enable-gmp --enable-libgme --enable-gray --enable-libaom --enable-libfribidi --enable-libass --enable-libvmaf --enable-libfreetype --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libopenjpeg --enable-librubberband --enable-libsoxr --enable-libspeex --enable-libsrt --enable-libvorbis --enable-libopus --enable-libtheora --enable-libvidstab --enable-libvo-amrwbenc --enable-libvpx --enable-libwebp --enable-libx264 --enable-libx265 --enable-libxml2 --enable-libdav1d --enable-libxvid --enable-libzvbi --enable-libzimg
 libavutil 56. 61.100 / 56. 61.100
 libavcodec 58.114.100 / 58.114.100
 libavformat 58. 64.100 / 58. 64.100
 libavdevice 58. 11.103 / 58. 11.103
 libavfilter 7. 91.100 / 7. 91.100
 libswscale 5. 8.100 / 5. 8.100
 libswresample 3. 8.100 / 3. 8.100
 libpostproc 55. 8.100 / 55. 8.100
Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'out.mp4':
 Metadata:
 major_brand : mp42
 minor_version : 0
 compatible_brands: isommp42
 creation_time : 2020-12-26T11:13:27.000000Z
 com.android.version: 10
 Duration: 00:00:03.27, start: 0.000000, bitrate: 21344 kb/s
 Stream #0:0(eng): Video: h264 (High) (avc1 / 0x31637661), yuv420p(tv, unknown/bt470bg/unknown), 1920x1080, 20225 kb/s, SAR 1:1 DAR 16:9, 29.99 fps, 30.01 tbr, 90k tbn, 180k tbc (default)
 Metadata:
 rotate : 90
 creation_time : 2020-12-26T11:13:27.000000Z
 handler_name : VideoHandle
 Side data:
 displaymatrix: rotation of -90.00 degrees
 Stream #0:1(eng): Audio: aac (LC) (mp4a / 0x6134706D), 48000 Hz, mono, fltp, 128 kb/s (default)
 Metadata:
 creation_time : 2020-12-26T11:13:27.000000Z
 handler_name : SoundHandle
[tcp @ 0x58bf880] Connection to tcp://a.rtmp.youtube.com:1935 failed: Connection timed out
[rtmp @ 0x5893140] Cannot open connection tcp://a.rtmp.youtube.com:1935
rtmp://a.rtmp.youtube.com/live2/my-key: Connection timed out







how to fix this, btw i use vps, sorry, my english so bad and this is the first time i asked on this website