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• ffmpeg record audio from Xvfb on Centos

  25 mai 2017, par boygiandi

  I’m trying to record audio from Xvfb. And I have some problems :

  1. What’s the different between alsa and pulse. I get confuse
  2. Server Centos have no soud card :

  arecord -l

  arecord : device_list:268 : no soundcards found...

  3. I may have many Xvfb process, how to record video and audio from specific Xvfb process. I checked this https://trac.ffmpeg.org/wiki/Capture/ALSA#Recordaudiofromanapplication but still don’t understand how it works.

  ffmpeg -f alsa -ac 2 -i hw:0,0 -acodec pcm_s16le output.wav

  I seen many command like this, but I don’t know how to get hw:0,0 ( id of sound card ? )

  Please help. Thanks

• Why am I getting an exit status of 1 ?

  24 mai 2018, par Akaisteph7

  So, I am writing this code to analyze this video but I am facing this issue when I try to run it in Spyder, Anaconda :

  import subprocess
  
  from subprocess import call
  
  import math
  
  
  
  ##Converts the given file into a series of images
  
  def Video_to_Image_Converter(fileName):
  
      res1 = call("ffmpeg -i " + fileName + " -vf fps=1 frame-%d.jpg", shell=True)
  
      print(res1)
  
      result = subprocess.Popen('ffprobe -i '+ fileName +' -show_entries format=duration -v quiet -of csv="p=0"', stdout=subprocess.PIPE,stderr=subprocess.STDOUT, shell=True)
  
      output = result.communicate()
  
      print(output)
  
      #return math.ceil(float(output[0])) + 1
  
  
  
  
  
  if __name__ == '__main__':
  
      videoLength = Video_to_Image_Converter('sampleVideo.wmv')
  
      print(videoLength)

  So, this code worked fine in iPython but I started having issues when trying to use Spyder. res1 should have an exit status of 0 if everything went well but it is 1. However, I do not know what went wrong. All it says when running subprocess.check_output on call is :

  Command 'ffmpeg -i sampleVideo.wmv -vf fps=1 frame-%d.jpg' returned non-zero exit status 1

  Please help.

• call ffmepg from apache php without full path

  14 février 2015, par ffmpeg fan

  I need a apache /php to recognize ffmpeg command without specifing the full bath of /usr/local/bin/ffmpeg

  calling ffmpeg from command line executes the program
  calling ffmpeg from php via web does not execute the program
  calling /usr/local/bin/ffmpeg from php via web does execute the program

  why :
  a php script calls youtube-dl (a compiled program) and executes ffmpeg internally

  thank you in advance -
  tried ffmpeg path :
  which ffmpeg
  /usr/local/bin/ffmpeg

  echo $PATH
  
  /usr/lib64/qt-3.3/bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/root/bin
  
  
  
  
  
  #php code for testing:
  
  $output = shell_exec('/usr/local/bin/ffmpeg 2>&1');
  
  echo "shell exec /usr/local/bin/ffmpeg <pre>$output</pre>";
  
  #Response:
  
  ffmpeg version 2.5.3 Copyright #(good)
  
  
  
  #Second php code for testing:
  
  $output = shell_exec('ffmpeg 2>&amp;1');
  
  echo "shell exec <pre>$output</pre>";
  
  #Response:
  
  sh: ffmpeg: command not found #(bad)