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Collections - Formulaire de création rapide
19 février 2013, par
Mis à jour : Février 2013
Langue : français
Type : Image
Autres articles (99)
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Publier sur MédiaSpip
13 juin 2013Puis-je poster des contenus à partir d’une tablette Ipad ?
Oui, si votre Médiaspip installé est à la version 0.2 ou supérieure. Contacter au besoin l’administrateur de votre MédiaSpip pour le savoir -
Submit bugs and patches
13 avril 2011Unfortunately a software is never perfect.
If you think you have found a bug, report it using our ticket system. Please to help us to fix it by providing the following information : the browser you are using, including the exact version as precise an explanation as possible of the problem if possible, the steps taken resulting in the problem a link to the site / page in question
If you think you have solved the bug, fill in a ticket and attach to it a corrective patch.
You may also (...) -
HTML5 audio and video support
13 avril 2011, parMediaSPIP uses HTML5 video and audio tags to play multimedia files, taking advantage of the latest W3C innovations supported by modern browsers.
The MediaSPIP player used has been created specifically for MediaSPIP and can be easily adapted to fit in with a specific theme.
For older browsers the Flowplayer flash fallback is used.
MediaSPIP allows for media playback on major mobile platforms with the above (...)
Sur d’autres sites (7823)
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Passing arguments to Powershells Call Operatore - I can't get it to work
2 janvier 2020, par morgola22For some reason I cannot get even the most simple Ffmpeg case to work :
$pathToFfmpeg = "PathToFfmpeg\ffmpeg.exe"
$video = "PathToVideoFile\video.mp4"
$param = "--i $video", "output.avi"
$execute = &$pathToFfmpeg $paramThis should result in the most basic Ffmpeg usage according to Ffmpeg website :
ffmpeg -i input.mp4 output.avi
.
However all I receive is :ffmpeg.exe : ffmpeg version git-2020-01-01-7b58702 Copyright (c) 2000-2020 the FFmpeg developers
At line:4 char:12
+ [string[]] $execute = &$pathToFfmpeg $param
+ ~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : NotSpecified: (ffmpeg version ...mpeg developers:String) [], RemoteException
+ FullyQualifiedErrorId : NativeCommandError
built with gcc 9.2.1 (GCC) 20191125
configuration: --enable-gpl --enable-version3 --enable-sdl2 --enable-fontconfig --enable-gnutls --enable-iconv --enable-libass
--enable-libdav1d --enable-libbluray --enable-libfreetype --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb
--enable-libopenjpeg --enable-libopus --enable-libshine --enable-libsnappy --enable-libsoxr --enable-libtheora --enable-libtwolame
--enable-libvpx --enable-libwavpack --enable-libwebp --enable-libx264 --enable-libx265 --enable-libxml2 --enable-libzimg --enable-lzma
--enable-zlib --enable-gmp --enable-libvidstab --enable-libvorbis --enable-libvo-amrwbenc --enable-libmysofa --enable-libspeex
--enable-libxvid --enable-libaom --enable-libmfx --enable-ffnvcodec --enable-cuvid --enable-d3d11va --enable-nvenc --enable-nvdec
--enable-dxva2 --enable-avisynth --enable-libopenmpt --enable-amf
libavutil 56. 38.100 / 56. 38.100
libavcodec 58. 65.100 / 58. 65.100
libavformat 58. 35.101 / 58. 35.101
libavdevice 58. 9.102 / 58. 9.102
libavfilter 7. 70.101 / 7. 70.101
libswscale 5. 6.100 / 5. 6.100
libswresample 3. 6.100 / 3. 6.100
libpostproc 55. 6.100 / 55. 6.100
Unrecognized option '-i PathToVideoFile\video.mp4'.
Error splitting the argument list: Option not foundSo it seems I am doing something wrong. Anybody knows how I get this to work ? I have tried different methods to create the params array and checked with EchoArgs.exe, but no avail. I am out of ideas. It looks like Ffmpeg does not recognise what Powershell is passing to it.
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vf_crop : make config_props work properly when called multiple times.
18 mars 2013, par Anton Khirnov -
ffmpeg works in command line but it doesn't work well in c#
14 août 2016, par Ahmad Ali MukashatyI want to stream movie via udp so I use this command line and it works well
ffmpeg -re -i test.mkv -q 1 -vcodec libx264 -f mpegts udp://network:port
but I want to run this command line using c# like this :
process = new Process();
process.StartInfo.FileName = "cmd.exe";
process.StartInfo.WorkingDirectory = @"c:\FFmpegTool\bin";
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.Arguments = "/C ffmpeg.exe";
process.Start();
process.StartInfo.FileName = "ffmpeg";
process.StartInfo.Arguments = "-re -i test.mkv -q 1 -vcodec libx264 -f mpegts udp://network:port";
process.Start();it works but I can’t receive the stream
why this commnand doesn’t work well when I use it in c# and what’s the different bettwen ranning command in cmd directly or using process class in c#