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• How to bind ffmpeg4.4 to OpenCV3.4.13 to work in Android Studio4.2.1 (Java)

  8 juin 2021, par Fab

  Finally opencv is working in my Android Studio project (solved with help of https://www.youtube.com/watch?v=-0Yx1UzozzQ). But theres is no Video I/O information visible so I guess i didnt connected ffmpeg correctly in my project and it isnt used at all !?

  


  My steps so far :

  


  


  • ffmpeg download : https://www.videohelp.com/software/ffmpeg

    


  


  • added ffmpeg to path like explained here :
https://soundartifacts.com/how-to/186-how-to-install-ffmpeg-on-windows-10-amp-add-ffmpeg-to-windows-path.html#video
. Powershell shows that ffmpeg is installed.

    


  


  • when printing Core.getBuildInformation() in the project I see that the Video I/O section is empty and I assume there has to be some information about FFMPEG etc...see picture :
enter image description here

    


  


  


  

  • I dont get any error messages. I try to VideoCapture.open("somestring") and return value is always false.

  


  


  I know there are a lot of similar questions but I cant identify which one really addresses my issue.
Really appreciate your help. Thanks, Fabian

  


• How to compile ffmpeg4.4 with OpenCV3.4.13 to work in Android Studio4.2.1 (Java) [closed]

  8 juin 2021, par Fab

  Finally opencv is working in my Android Studio project (solved with help of https://www.youtube.com/watch?v=-0Yx1UzozzQ). But theres is no Video I/O information visible so I guess i didnt connected ffmpeg correctly in my project and it isnt used at all !?

  


  My steps so far :

  


  


  • ffmpeg download : https://www.videohelp.com/software/ffmpeg

    


  


  • added ffmpeg to path like explained here :
https://soundartifacts.com/how-to/186-how-to-install-ffmpeg-on-windows-10-amp-add-ffmpeg-to-windows-path.html#video
. Powershell shows that ffmpeg is installed.

    


  


  • when printing Core.getBuildInformation() in the project I see that the Video I/O section is empty and I assume there has to be some information about FFMPEG etc...see picture :
enter image description here

    


  


  


  

  • I dont get any error messages. I try to VideoCapture.open("somestring") and return value is always false.

  


  


  I know there are a lot of similar questions but I cant identify which one really addresses my issue.
Really appreciate your help. Thanks, Fabian

  


• How to setup ffmpeg for linux server

  1er décembre 2014, par hitesh

  I need to create a screen shot from video,

  I have followed this tutorial to do the intial setup in window 8, php 5.3

  1) I downloaded the ffmpeg from here -[
  http://ffmpeg.zeranoe.com/builds/ ] for 64 bit operating system.

  2) I followed the https://www.youtube.com/watch?v=gU49GiWGGAI , video and did all configuration successfully and phpinfo() shows that ffmpeg has been installed.

  3) Then I tried this to find out whether it is working or not,

  It worked successfully

  4) Next I followed this video tutorial here and thumbnails were created successfully.

  below is my code

  /**
  
   * FFMPEG-PHP Test Script
  
   *
  
   * Special thanks to http://www.sajithmr.me/ffmpeg-sample-code for this code example!
  
   * See the tutorial at http://myownhomeserver.com on how to install ffmpeg-php.
  
   */
  
  error_reporting(1);
  
  error_reporting(E_ALL ^ E_NOTICE);
  
  // Check if the ffmpeg-php extension is loaded first
  
  extension_loaded('ffmpeg') or die('Error in loading ffmpeg');
  
  
  
  // Determine the full path for our video
  
  $vid = realpath('./videos/myvideo.mp4');
  
  $videosize = filesize($vid);
  
  $remoteVideo = 'http://video-js.zencoder.com/oceans-clip.mp4';
  
  
  
  //ffmpeg
  
  
  
  $ffmpeg = dirname(__FILE__) . "\\ffmpeg\\bin\\ffmpeg";
  
  $imageFile = "1.png";
  
  $image2 = "2.png";
  
  $size = "120x90";
  
  $getfromsecond = 7;
  
  $cmd = "$ffmpeg -i $vid -an -ss $getfromsecond -s $size $imageFile";
  
  $cmd2 = "$ffmpeg -i $remoteVideo -an -ss $getfromsecond -s $size $image2";
  
  if(!shell_exec($cmd)){
  
      echo "Thumbnail created";
  
  }else{
  
      echo "Error Creating thumbnail";
  
  }
  
  
  
  if(!shell_exec($cmd2)){
  
      echo "Thumbnail for remote url was created";
  
  }else{
  
      echo "Error Creating thumbnail for remote url ";
  
  }

  ---

    OUTPUT
  
      Thumbnail created
  
      Thumbnail for remote url was created

  Now above code works as expected in my local, in window machine , I need to do it in my server environment(Linux server) with php 5.5. How do I do the configuration for ffmpeg in linux server with php 5.5.