Recherche avancée

Sur d’autres sites (7408)

• How to use (django-celery,RQ) worker to execute a video filetype conversion (ffmpeg) in django on heroku (My code works locally)

  15 janvier 2013, par GetItDone

  One part of my website includes a form that allows users to upload video. I use ffmpeg to convert the video to flv. My media and static files are stored on Amazon S3. I can get everything to work perfectly locally, however I can't seem to figure out how to use a worker to run the video conversion subprocess in production. I have dj-celery and rq installed in my app. The code in my view that I was able to get to work locally is :

  #views.py
  
  def upload_broadcast(request):
  
      if request.method == 'POST':
  
          form = VideoUploadForm(request.POST, request.FILES)
  
          if form.is_valid():
  
              new_video=form.save()
  
              def convert_to_flv(video):
  
                  filename = video.video_upload
  
                  sourcefile = "%s%s" % (settings.MEDIA_ROOT, filename)
  
                  flvfilename = "%s.flv" % video.id
  
                  imagefilename = "%s.png" % video.id
  
                  thumbnailfilename = "%svideos/flv/%s" % (settings.MEDIA_ROOT, imagefilename)
  
                  targetfile = "%svideos/flv/%s" % (settings.MEDIA_ROOT, flvfilename)
  
                  ffmpeg = "ffmpeg -i %s -acodec mp3 -ar 22050 -f flv -s 320x240 %s" % (sourcefile, targetfile)
  
                  grabimage = "ffmpeg -y -i %s -vframes 1 -ss 00:00:02 -an -vcodec png -f rawvideo -s 320x240 %s" % (sourcefile, thumbnailfilename)
  
                  print ("SOURCE: %s" % sourcefile)
  
                  print ("TARGET: %s" % targetfile)
  
                  print ("TARGET IMAGE: %s" % thumbnailfilename)
  
                  print ("FFMPEG TASK CODE: %s" % ffmpeg)
  
                  print ("IMAGE TASK CODE: %s" % grabimage)
  
                  try:
  
                      ffmpegresult = subprocess.call(ffmpeg)
  
                      print "---------------FFMPEG---------------"
  
                      print ffmpegresult
  
                  except:
  
                      print "Not working."
  
                  try:
  
                      videothumbnail = subprocess.call(grabimage)
  
                      print "---------------IMAGE---------------"
  
                      print videothumbnail
  
                  except:
  
                      print "Not working."
  
                  video.flvfilename = flvfilename
  
                  video.videothumbnail = imagefilename
  
                  video.save()
  
  
  
              convert_to_flv(new_video)
  
  
  
              return HttpResponseRedirect('/video_list/')
  
      else:
  
  ...

  This is my first time trying to use a worker (or ever pushing a project to production), so even with the documentation it is still unclear to me what I need to do. I have tried several different things but nothing seems to work. Is there just a simple way to tell celery to run the ffmpegresult = subprocess.call(ffmpeg) ? Thanks in advance for any help or insight.

  EDIT- Added heroku logs

  2013-01-10T20:58:57+00:00 app[web.1]: TARGET: /media/videos/flv/8.flv
  
  2013-01-10T20:58:57+00:00 app[web.1]: IMAGE TASK CODE: ffmpeg -y -i /media/videos/practice.wmv -vframes 1 -ss 00:00:02 - an -vcodec png -f rawvideo -s 320x240 /media/videos/flv/8.png
  
  2013-01-10T20:58:57+00:00 app[web.1]: SOURCE: /media/videos/practice.wmv
  
  2013-01-10T20:58:57+00:00 app[web.1]: FFMPEG TASK CODE: ffmpeg -i /media/videos/practice.wmv -acodec mp3 -ar 22050 -f fl v -s 320x240 /media/videos/flv/8.flv
  
  2013-01-10T20:58:57+00:00 app[web.1]: TARGET IMAGE: /media/videos/flv/8.png
  
  2013-01-10T20:58:57+00:00 app[web.1]: Not working.
  
  2013-01-10T20:58:57+00:00 app[web.1]: Not working.

  NEWER EDIT

  I tried adding a tasks.py and added the task :

  celery = Celery('tasks', broker='redis://guest@localhost//')
  
  
  
  @celery.task
  
  def ffmpeg_task(video):
  
      converted_file = subprocess.call(video)
  
      return converted_file

  then I changed the relevant section of my view to :

  ...
  
  try:
  
      ffmpeg_task.delay(ffmpeg)
  
      print "---------------FFMPEG---------------"
  
      print ffmpegresult
  
  except:
  
      print "Not working."
  
  ...

  My new logs are :

  2013-01-15T13:19:52+00:00 app[web.1]: TARGET IMAGE: /media/videos/flv/12.png
  
  2013-01-15T13:19:52+00:00 app[web.1]: SOURCE: /media/videos/practice.wmv
  
  2013-01-15T13:19:52+00:00 app[web.1]: FFMPEG TASK CODE: ffmpeg -i /media/videos/practice.wmv -acodec mp3 -ar 22050 -f fl v -s 320x240 /media/videos/flv/12.flv
  
  2013-01-15T13:19:52+00:00 app[web.1]: IMAGE TASK CODE: ffmpeg -y -i /media/videos/practice.wmv -vframes 1 -ss 00:00:02 -an -vcodec png -f rawvideo -s 320x240 /media/videos/flv/12.png
  
  2013-01-15T13:19:52+00:00 app[web.1]: TARGET: /media/videos/flv/12.flv
  
  2013-01-15T13:20:17+00:00 app[web.1]: 2013-01-15 13:20:17 [2] [CRITICAL] WORKER TIMEOUT (pid:12)
  
  2013-01-15T13:20:17+00:00 app[web.1]: 2013-01-15 13:20:17 [2] [CRITICAL] WORKER TIMEOUT (pid:12)
  
  2013-01-15T13:20:17+00:00 app[web.1]: 2013-01-15 13:20:17 [19] [INFO] Booting worker with pid: 19

  Am I completely missing something ? I'll keep trying, but will be very appreciative of any direction or assistance.

• Continously running a PHP script waiting for videos to trancode

  12 mai 2017, par Ian

  I’m making a transcoding server which uses FFMPEG to convert videos to flv. After user uploads a video it’s queued for processing in amazon Simple Queue Service. System is linux ubuntu.

  Instead of running CRON each 1min I wonder if it would be possible to continously run several PHP scripts (dowload queued files, process downloaded etc). Each of them would have its own queue which would be read every 10s or so looking for new tasks.

  My question is :

  How to detect if the script is already running ? I’d run CRON each 1min and if one of the programs would not be running I’d load it again. How stuff like that is done on linux ? PID files ?

  thanks for help,
  ian

• is Cloud API's needed for Video Conversion to save huge time ?

  4 mai 2017, par user2224250

  I have seen a couple of ffmpeg software’s which converts a video x format (1.8 GB) to y format (1.8 GB) in less than 90 seconds

  For example IDealshare VideoGo

  When I work with ffmpeg in the terminal, these sort of conversions takes atleast one hour. Moreover, when I compare to the above software, am facing a very very big number interms of time.

  May be, do you think for these fast conversions, we must take help from third party cloud API’s (software’s) such as amazon elastic transcoder etc etc.

  Any pointers would be really appreciable !!